QUESTION:
The %age of three elements calcium, carbon and oxygen in a sample of calcium carbonate is given as-
calcium-40%, carbon-12%, oxygen-48%.
If the law of constant proportion is true, what weights of each elements will be present in 1.5 g of another sample of calcium carbonate?
ANSWER:
Given the atomic mass of ca- 40u. c-12u, o-16u.
Mass=(1) calcium-1.5 x 40/100 = 0.6
(2)carbon-1.5 x 12/100= 0.18
(3)oxygen-1.5 x 48/100= 0.72
Moleculer Weight=(1)calcium-40 x 0.6= 24
(2)carbon-12 x 0.8= 2.16
(3)oxygen-16 x 0.72= 11.52
The %age of three elements calcium, carbon and oxygen in a sample of calcium carbonate is given as-
calcium-40%, carbon-12%, oxygen-48%.
If the law of constant proportion is true, what weights of each elements will be present in 1.5 g of another sample of calcium carbonate?
ANSWER:
Given the atomic mass of ca- 40u. c-12u, o-16u.
Mass=(1) calcium-1.5 x 40/100 = 0.6
(2)carbon-1.5 x 12/100= 0.18
(3)oxygen-1.5 x 48/100= 0.72
Moleculer Weight=(1)calcium-40 x 0.6= 24
(2)carbon-12 x 0.8= 2.16
(3)oxygen-16 x 0.72= 11.52
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